The zeros of the
polynomial x^2-√2x-12
1)√2,-√2
2)3√2,-2√2
3) -3√2,2√2
4) 3√2,2√2​

1 thought on “<br />The zeros of the<br />polynomial x^2-√2x-12<br />1)√2,-√2<br />2)3√2,-2√2<br />3) -3√2,2√2<br />4) 3√2,2√2​”

1. Answer:

   option B is correct

   Step-by-step explanation:

   We have, f(x) = x2 ‒ √2x – 12

   Now, put f(x) = 0

   x2 ‒ √2x – 12 = 0

   x2 – 3√2x + 2√2x – 12 = 0

   x(x ‒ 3√2) + 2√2(x – 3√2)=0

   (x ‒ 3√2) + (x + 2√2) = 0

   Thus, x= 3√2 , -2√2

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