The unit place digit in 2^50 x 5^48 – 9 is tennetiraj please help for my questions​

The unit place digit in 2^50 x 5^48 – 9 is tennetiraj please help for my questions​

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  1. Step-by-step explanation:

    Given :

    2^50 x 5^48 – 9

    To find :

    The unit place digit in 2^50 x 5^48 – 9 ?

    Solution :

    Given number is 2^50 x 5^48 – 9

    2^50 = 2×2×2×…×(50 times)

    2^1 = 2

    2^2 = 4

    2^3 = 8

    2^4 = 16

    2^5 = 32

    2^6 = 64…

    If you continues the unit places are 2,4,8,6.They repeat agin again

    2^50 = (2^5)^10

    The units place of 2^50 = 4

    and 5^48

    5^1 = 5

    5^2 = 25

    We continue like this we get always 5 in its units place

    => The unit digit in 5^48 is 5

    Now

    The unit place of 2^50×5^48 is

    => 4×5

    => 20

    Unit place is 0

    and given that

    The unit place of 2^50 x 5^48 – 9

    We have 0 as units place of the product and

    9 is subtracted from the product

    So The required digit must be 10-9 = 1

    Answer:

    The unit place for the given problem is 1

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