The tops of two poles of height 20m and 14m are connected by a wire if the wire makes an angle of 30⁰ with origin till then the length of the wire is About the author Emery

Given : The tops of two poles of height 20m and 14m are connected by a wire. The wire makes an angle of 30 degrees with horizontal To find: the length of the wire Solution: Height of one pole = 20 m Height of another pole = 14 m Height of bigger pole above the top of Smaller pole = 20 – 14 = 6 m Let sat length of the wire = L m the wire makes an angle of 30 degrees with horizontal, => Sin 30° = 6 /L => 1/2 = 6/L => L = 12 Length of Wire = 12 m Reply

Answer: correct answer is Step-by-step explanation: Given that : Heights of two poles are 20 and 14m respectively. Angle wire makes with horizontal =30∘ Let distance between two poles be x and length of wire be y tan30∘=x20−14=x6 31=x6 ⇒x=63 As length of the wire will form the hypotenuse of right angled triangle thus formed, y2=62+(63)2=144 ∴y=12 m Reply

Given :The tops of two poles of height 20m and 14m are connected by a wire. The wire makes an angle of 30 degrees with horizontalTo find: the length of the wire## Solution:

Height of one pole = 20 m

Height of another pole = 14 m

Height of bigger pole above the top of Smaller pole = 20 – 14 = 6 m

Let sat length of the wire = L m

the wire makes an angle of 30 degrees with horizontal,

=> Sin 30° = 6 /L

=> 1/2 = 6/L

=> L = 12

Length of Wire = 12 mAnswer:correct answer is

Step-by-step explanation:Given that : Heights of two poles are 20 and 14m respectively.

Angle wire makes with horizontal =30∘

Let distance between two poles be x and length of wire be y

tan30∘=x20−14=x6

31=x6

⇒x=63

As length of the wire will form the hypotenuse of right angled triangle thus formed,

y2=62+(63)2=144

∴y=12 m