Let the two numbers be x and y. Given, x + y = 32 x = 32 – y…. (I) x – y = 22 32 – y – y = 22 – 2y = 22 – 32 y = -10 / – 2 y = 5….(II) Putting the value of y in equation (I), we have x = 32 – 5 x = 27 Therefore, the two values are 27 and 5 respectively. Hope it helps. Reply
Answer: Let the two numbers be x and y Accto question= x+y=32(1) and x-y=22(2) from equation (1) x=32-y(3) putting value of x in equation 2 32-y-y=22 32-22=2y 10=2y y=5 Now putting value of y in equation 3 x=32-5=27 Hence value of two numbers is 27 and 5 Reply
Let the two numbers be x and y.
Given,
x + y = 32
x = 32 – y…. (I)
x – y = 22
32 – y – y = 22
– 2y = 22 – 32
y = -10 / – 2
y = 5….(II)
Putting the value of y in equation (I), we have
x = 32 – 5
x = 27
Therefore, the two values are 27 and 5 respectively.
Hope it helps.
Answer:
Let the two numbers be x and y
Accto question= x+y=32(1)
and x-y=22(2)
from equation (1) x=32-y(3)
putting value of x in equation 2
32-y-y=22
32-22=2y
10=2y
y=5
Now putting value of y in equation 3
x=32-5=27
Hence value of two numbers is 27 and 5