the sum of the 2digit no. and the no. obtained be the reversing the order of ts digit is 99.if the digit differ by 3.find the no.? About the author Arianna
Answer: 36 Step-by-step explanation: Let the 2 digits be x,y. respectively 2 digit number =10x+y 2 digit number obtained by ususing the digit =10y+x ∴10x+y+10y+x=99 ⇒11x+11y=99 ⇒x+y=9 x−y=3 On adding : 2x=12 x=6 putting x in ⟶(i) 6+y=9 y=3 ∴ Number =10x+y=63 or , 10y+x=36. Reply
Step-by-step explanation: Let the 2 digits be x,y. respectively 2 digit number =10x+y 2 digit number obtained by ususing the digit =10y+x ∴10x+y+10y+x=99 ⇒11x+11y=99 ⇒x+y=9 x−y=3 On adding : 2x=12 x=6 putting x in ⟶(i) 6+y=9 y=3 ∴ Number =10x+y=63 or , 10y+x=36. Reply
Answer:
36
Step-by-step explanation:
Let the 2 digits be x,y. respectively
2 digit number =10x+y
2 digit number obtained by ususing the digit =10y+x
∴10x+y+10y+x=99
⇒11x+11y=99
⇒x+y=9
x−y=3
On adding : 2x=12
x=6
putting x in ⟶(i)
6+y=9
y=3
∴ Number =10x+y=63
or , 10y+x=36.
Step-by-step explanation:
Let the 2 digits be x,y. respectively
2 digit number =10x+y
2 digit number obtained by ususing the digit =10y+x
∴10x+y+10y+x=99
⇒11x+11y=99
⇒x+y=9
x−y=3
On adding : 2x=12
x=6
putting x in ⟶(i)
6+y=9
y=3
∴ Number =10x+y=63
or , 10y+x=36.