the sum of a whole number and twice the square of the number is is 80. find the number? About the author Faith
Given – The sum of a whole number and twice the square of the number is 80. Find – The whole number. Solution – The equation as per mentioned details will be : X + 2x² = 80. Taking all the variables to left side, equation will be : 2x² + X -80 = 0 Solving the formed quadratic equation by Shri Dharacharya formula – -b +- ✓(b² – 4*a*c)/2*a. Keeping the values in equation- X = -1 +- ✓(1² -4*2*80)/2*2 X = (-1 +- ✓641)/4 Since x is an whole number, ignoring the negative answer. X = 24.3/4 X = 6.08. Rounding the resultant value of X to nearest whole number, X = 6. Hence, the nearest whole number is 6. Reply
Answer:
Number is 20 which has square as 40 and twice it is 80
Given – The sum of a whole number and twice the square of the number is 80.
Find – The whole number.
Solution – The equation as per mentioned details will be : X + 2x² = 80.
Taking all the variables to left side, equation will be : 2x² + X -80 = 0
Solving the formed quadratic equation by Shri Dharacharya formula –
-b +- ✓(b² – 4*a*c)/2*a.
Keeping the values in equation-
X = -1 +- ✓(1² -4*2*80)/2*2
X = (-1 +- ✓641)/4
Since x is an whole number, ignoring the negative answer.
X = 24.3/4
X = 6.08.
Rounding the resultant value of X to nearest whole number, X = 6.
Hence, the nearest whole number is 6.