The sum of 3 numbers in a AP is 12 and sum of their cubes is 288. find the numbers About the author Adalynn
Answer: 3,4,5 are the A.P Step-by-step explanation: hope this would help if then please mark as brainliest Reply
Thus, we have a−d+a+a+d=12. We have to now find the value of common difference d. We know that the sum of cubes of the numbers is 288. Thus, we have (a−d)3+a3+(a+d)3=288. Reply
Answer:
3,4,5 are the A.P
Step-by-step explanation:
hope this would help if then please mark as brainliest
Thus, we have a−d+a+a+d=12. We have to now find the value of common difference d. We know that the sum of cubes of the numbers is 288. Thus, we have (a−d)3+a3+(a+d)3=288.