The solution of differential equation
4 4 5 0
2
2
  y 
dx
dy
dx
d y
is<

by

The solution of differential equation
4 4 5 0
2
2
  y 
dx
dy
dx
d y
is
a) x e

(c1cos2x+c2 sin2x) b) x / 2 e

(c1cosx+c2 sinx)
c) x e
2
(c1cosx+c2 sinx) d) c1 x e
4 + c

1 thought on “The solution of differential equation <br /> 4 4 5 0<br /> 2<br /> 2<br />   y <br /> dx<br /> dy<br /> dx<br /> d y<br /> is<”

  1. Answer:

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