The small piston of a hydraulic lift has an area of 6 cm 2and its large piston has an area of 54 cm 2 . A 50 N force is applied to

Question

The small piston of a hydraulic lift has an area of 6 cm 2and its large piston has an area of 54 cm 2 . A 50 N force is applied to the small piston. What is the weight of the load can be lifted by the large piston?

Madeline · Answer

Answer:   Area 1 = 6 cm²   Area 2 = 54 cm²  Force 1 = 50 N  Force 2 = ? N    We know the formula that :  Force 2 by Force 1 = Area 2 by Area 1  Force 2 by 50 = 54 by 6  Force 2 = 50 × 54 divided by 6  Force 2 = 50 × 9  Force 2 = 450 N    Answer .    Please mark me as a brainlist answer .

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