The set of values of ‘x’ satisfying (x²-x-1)(x²-x-7)<-5 is (a,b)U(c,d) then a+b+c+d is equal to About the author Amelia
Answer: Answer Open in answr app Open_in_app (x 2 −x−1)(x 2 −x−7)<−5 Let x 2 −x be t (t−1)(t−7)<−5 t 2 −8t+7+5<0 t 2 −8t+12<0 (t−6)(t−2)<0 (x 2 −x−6)(x 2 −x−2)<0 (x−3)(x+2)(x−2)(x+1)<0 x∈(−2,−1)∪(2,3) Reply
Answer:
Answer
Open in answr app
Open_in_app
(x
2
−x−1)(x
2
−x−7)<−5
Let x
2
−x be t
(t−1)(t−7)<−5
t
2
−8t+7+5<0
t
2
−8t+12<0
(t−6)(t−2)<0
(x
2
−x−6)(x
2
−x−2)<0
(x−3)(x+2)(x−2)(x+1)<0
x∈(−2,−1)∪(2,3)