The ratio between length and breadth of a field is 10 : 6. The area of the field is 3840m². Find the difference between the length

2 thoughts on “The ratio between length and breadth of a field is 10 : 6. The area of the field is 3840m². Find the difference between the length”

1. By using the required fоrmulа, аnd substituting аll the given vаlues in the fоrmulа, we get:

   → Аreа оf seсtоr

   = 60/360 × 22/7 × (7)²

   → Аreа оf seсtоr

   = 6/36 × 22/7 × 7 × 7

   → Аreа оf seсtоr

   = 1/6 × 22/7 × 7 × 7

   → Аreа оf seсtоr

   = 1/6 × 22 × 7

   → Аreа оf seсtоr

   = 1/3 × 11 × 7

   → Аreа оf seсtоr

   = 1/3 × 77

   → Аreа оf seсtоr

   = 77/3

   → Аreа оf seсtоr

   = 25.66

   → Аreа оf seсtоr

   ≈ 26. (аррrоx.)

   Henсe, the аreа оf seсtоr is 26сm², орtiоn (с) is соrreсt.

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2. The difference between the length and width of the rectangular field are 32 m.

   Given :

   • The ratio between length and breadth of a rectangular field is 10 : 6. The area of the rectangular field is 3840m2.

   To Find :

   The difference between the length and width of the rectangular field.

   Solution :

   Let us assume that, the length of a rectangle is 10x m and the breadth of a rectangle is 6x m respectively.

   As we know that

   Area of rectangle = length * breadth

   =3840 = 10x * 6x

   oo

   = 3840 = 60x²

   – x2 = 3840/60

   → x² = 384/6

   – x² = 64

   – x = V64

   = x = 8

   Therefore,

   = Length of a rectangle = 10x

   = Length of a rectangle = 10 * 8

   » Length of a rectangle = 80m

   – Breadth of a rectangle = 6x

   – Breadth of a rectangle = 6 * 8 =48m.

   Now,

   The difference between the length and width

   of the rectangular field :

   Length – Breadth

   80 – 48

   32m.

   Reply