The radius of a cylindrical tank is 14 m. And height 20 m. Is.Find the area of ​​curvature of the cylindrical tank.(ii) Find the t

2 thoughts on “The radius of a cylindrical tank is 14 m. And height 20 m. Is.Find the area of ​​curvature of the cylindrical tank.(ii) Find the t”

1. Given :

   • Radius of Cylinderal tank = 14cm
   • Height of Cylinderal tank = 20cm

   To Find :

   • Area of curvature of the cylindrical tank
   • Total surface area of a cylindrical tank.
   • Volume of a cylindrical tank.

   Solution :

   (i) Curvature of Cylinderal tank

   CSA of cylinder = 2πrh

   CSA of cylinder = 2 × 22/7 × 14 × 20

   CSA of cylinder = 44 × 2 × 20

   CSA of cylinder = 88 × 20

   CSA of cylinder = 1760cm²

   (ii) Total surface area of cylinder

   TSA of cylinder = 2πr (h + r)

   TSA of cylinder = 2 × 22/7 × 14 (14 + 20)

   TSA of cylinder = 44 × 2 × 34

   TSA of cylinder = 88 × 34

   TSA of cylinder = 2992cm²

   (iii) Volume of cylinder

   Volume of cylinder = πr²h

   Volume of cylinder = 22/7 × 14 × 14 × 20

   Volume of cylinder = 44 × 14 × 20

   Volume of cylinder = 12320cm³

   Therefore,

   • CSA of cylinder is 1760cm²

   • TSA of cylinder is 2992cm²

   • Volume of cylinder is 12320cm³

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2. Answer:

   radius of tank, r = 14 m

   height of tank ,h= 20 m

   area of curvature = Curved Surface area = 2π rh

   [tex]2 \times \frac{22}{7} \times 14 \times 20 \\ 1760 {m}^{2} [/tex]

   total surface area. =2πr(r+h)

   [tex]2 \times \frac{22}{7} \times 14(14 + 20) \\ = 88 \times 34 = 2992 {m}^{2} [/tex]

   volume of cylindrical tank =πr²h

   [tex] \frac{22}{7} \times 14 \times 14 \times 20 = 43120 {m}^{3} [/tex]

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