c) p + 1. (d) p. 20. m² – 1 is divisible by 8, if m is. (a) an even integer (b) an odd integer √ (c) a … For some integersp and 5, there exist unique integers q and r such that p – 5q + r. … If product of two numbers is 3691 and their LCM is 3691, find their HCF. … Verify that x = 3 is a zero of the polynomial. p(x) = 2×3 – 5x² – 4x + 3.
Answer:
-4 is an answer
[tex]because \: \alpha \beta \gamma = – \frac{d}{a} \\ then \\ \: – \frac{8}{2} = – 4 \\ hope \: it \: will \: correct \: and \: helpful[/tex]
Answer:
Hi bro
Step-by-step explanation:
c) p + 1. (d) p. 20. m² – 1 is divisible by 8, if m is. (a) an even integer (b) an odd integer √ (c) a … For some integersp and 5, there exist unique integers q and r such that p – 5q + r. … If product of two numbers is 3691 and their LCM is 3691, find their HCF. … Verify that x = 3 is a zero of the polynomial. p(x) = 2×3 – 5x² – 4x + 3.