The pillars of a temple are cylindrically shaped. If each pillar has a circular base
of radius 1m and height 10m, find its vo

2 thoughts on “The pillars of a temple are cylindrically shaped. If each pillar has a circular base<br />of radius 1m and height 10m, find its vo”

1. Given : Base Radius of Pillar of temple is 1 m & Height of the Pillar is 10 m .

   Exigency To Find : Volume of Pillar .

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   ❍ Formula for Volume of Cylinder is given by :

   [tex]\dag\:\:\boxed{\sf{ Volume _{(Cylinder)} =\bigg( \pi r^2 h \bigg) }}\\\\[/tex]

   Where,

   • r is the Radius of Pillar , h is the Height of pillar & [tex]\pi = \dfrac{22}{7}\:or\:3.14[/tex]

   ⠀⠀⠀⠀⠀⠀[tex]\underline {\bf{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\[/tex]

   [tex]\qquad :\implies \sf { Volume = \dfrac{22}{7} \times (1)^2 \times 10 }\\\\\\ :\implies \sf { Volume = \dfrac{22}{7} \times 1 \times 10 }\\\\\\ :\implies \sf { Volume = 3.14 \times 1 \times 10 }\\\\\\ :\implies \sf { Volume = 3.14 \times 10 }\\\\\\ \underline {\boxed{\pink{ \frak { Volume = 31.4\: m^2}}}}\:\bf{\bigstar}\\[/tex]

   Therefore,

   ⠀⠀⠀⠀⠀[tex]\therefore {\underline{ \mathrm { Hence,\:The\:Volume \: \:of\:Pillar \:is\:\bf{31.4\: m^2}}}}\\[/tex]

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   [tex]\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}\\\\[/tex]

   [tex]\boxed{\begin{array}{cc}\bigstar$\:\underline{\textbf{Formulae Related to Cylinder :}}\\\\\sf {\textcircled{\footnotesize\textsf{1}}} \:Area\:of\:Base\:and\:top =\pi r^2 \\\\ \sf {\textcircled{\footnotesize\textsf{2}}} \:\:Curved \: Surface \: Area =2 \pi rh\\\\\sf{\textcircled{\footnotesize\textsf{3}}} \:\:Total \: Surface \: Area = 2 \pi r(h + r)\\ \\{\textcircled{\footnotesize\textsf{4}}} \: \:Volume=\pi r^2h\end{array}}[/tex]

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2. Answer:-

   The Volume of each pillar is 31.4 m³.

   Explanation:–

   Given:–

   • Radius of the pillar = 1m.
   • Height of the pillar = 10m.

   To Find:–

   • The Volume Of The Pillar.

   Formula Used:-

   [tex]\large\bf\mapsto V = \pi r^2 h.[/tex]

   Where,

   • V = Volume.
   • r = radius of the pillar = 1m.
   • [tex]\tt\pi = 3.14.[/tex]
   • h = height = 10m.

   Solution:–

   By Putting The Values In The Formula:-

   [tex]\\ \tt\mapsto V = \pi r^2 h.[/tex]

   [tex]\\ \tt\mapsto V =3.14 \times (1m) {}^{2} \times 10m.[/tex]

   [tex]\\ \tt\mapsto V =3.14 \times 1m {}^{2} \times 10m. [/tex]

   [tex]\\ \large\bf\mapsto \boxed{ \bf V =31.4 {m}^{3}} [/tex]

   Therefore The Required Volume of The Pillar Is 31.4 m³.

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