the perimeter of the rectangle is 130cm. if the length of the rectangle is 10cm less than twice of its breadth, find the number o

the perimeter of the rectangle is 130cm. if the length of the rectangle is 10cm less than twice of its breadth, find the number of the rectangle. by equation coefficient method​

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2 thoughts on “the perimeter of the rectangle is 130cm. if the length of the rectangle is 10cm less than twice of its breadth, find the number o”

  1. Perimeter of rectangle=130cm

    ⇒2(length+breadth)=130cm

    ⇒2(length+30)=130

    ⇒ length+30=
    2
    130

    ⇒ length+30=65

    ⇒ length=65−30=35cm

    Now area of rectangle=length×breadth=35×30=1050cm
    2

    Thus, the area of rectangle is 1050cm
    2
    .

    Reply
  2. Step-by-step explanation:

    Perimeter of rectangle=130cm

    ⇒2(length+breadth)=130cm

    ⇒2(length+30)=130

    ⇒ length+30=

    2

    130

    ⇒ length+30=65

    ⇒ length=65−30=35cm

    Now area of rectangle=length×breadth=35×30=1050cm

    2

    Thus, the area of rectangle is 1050cm

    2

    Reply

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