The perimeter of the floor of a room is 500m. Its length is 10m more than thrice its breadth. Calculate the length and the breadth of the room. Please answer fast….

The perimeter of a floor is given to us. We have to find it’s length and breadth. Let’s use the information given to us for forming an equation and solve it to get our answer!

Let :–

The breadth of the floor be “x” m.

It has been giventhat :–

The length of the floor is 10 m more than thrice it’s breadth.

Therefore,

The length of the floor will be “3x + 10” m.

Now,we knowthat :–

[tex] \underline{ \boxed{\sf Perimeter \: of \: a \: rectangle = 2 \: (L + B)}}[/tex]

Answer:Step-by-step explanation:The sum of consecutive multiple of 6 is 186. Find its two multiples

Answer:–Tofind:–Solution:–Let:–Ithasbeengiventhat:–Therefore,Now,weknowthat:–[tex] \underline{ \boxed{\sf Perimeter \: of \: a \: rectangle = 2 \: (L + B)}}[/tex]

Where,Here,Substitutingthegivenvaluesinthisformula,[tex] \longmapsto\rm500 = 2 \: (3x + 10 + x)[/tex]

[tex] \longmapsto\rm500 = 2 \: (4x + 10)[/tex]

[tex] \longmapsto\rm500 = 8x + 20[/tex]

[tex] \longmapsto\rm500 – 20 = 8x[/tex]

[tex] \longmapsto\rm480 = 8x[/tex]

[tex] \longmapsto\rm\dfrac{480}{8} = x[/tex]

[tex] \longmapsto\overline{ \boxed{ \rm60 \: m = x}}[/tex]

–––––––––––––––––––––––––––––––––––––––––––––––––––––––––––Therefore,thedimensionsoftheroomareasfollows:–[tex] \sf Length = 3x + 10 = 3 \times 60 + 10 = 190 \: m.[/tex]

[tex] \sf Breadth = x = 60 \: m.[/tex]