Answer: 68 Step-by-step explanation: Given, Tn=5n2−2 So, T1=5−2=3 T2=5(22)−2=18 T3=5(32)−2=47 So, Sum of first three terms =3+18+47=68 Reply
Answer:
68
Step-by-step explanation:
Given, Tn=5n2−2
So, T1=5−2=3
T2=5(22)−2=18
T3=5(32)−2=47
So, Sum of first three terms =3+18+47=68