The mean of eight numbers in a set is 41. The mean of two numbers in the set is 29. Calculate the mean of the remaining 6 numbers

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Isabella · Answer

Step-by-step explanation:       __________________________________________________________________________________________________________________              large pink{ { boxed { Question :-}}}   ⊙ The mean of eight numbers in a set is 41. The mean of two numbers in the set is 29. Calculate the mean of the remaining 6 numbers.    _________________________________________________________             Huge boxed {{  orange{Answer :-}}}           _________________________________________________________       implies {a+b+c+d+e+f+g+h}=328        implies frac{a + b  + c + d + e + f + g + h }{8} =41        implies  frac{g + h}{2}=29      g + h=58      So   implies a+b+c+d+e+f+g+h=328 Becomes...        implies  : a+b+c+d+e+f+58=328      implies  : a+b+c+d+e+f=270      implies  : Mean   : of   : these  :  six  :  numbers...      implies  frac{a + b + c + d + e + f + g}{6}=  frac{270}{6}=   pink{ boxed {45}}      green{  boxed{  implies{45}}}       _________________________________________________________      Explanation:    The mean is that single value that if you multiply it by the count of values used to derive it you end up with their sum.  8 values with mean of 41  8 x 41 = 328 <-sum of all values.  2 values with mean of 29  2 x 29 = 58  ~~~~~~~~~~~~~~~~~~~~~~~~  So the remaining 6 values must sum to 328 - 58 = 270  Thus the mean of the remaining 6 is 270÷6=45      _________________________________________________________

Sophia

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4. Mala bought 1/2m ribbon and Sheela bought 1/4m ribbon. What is the total length of
the ribbon bought by both

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