the length of a rectangular farm is 60 m. width 20m. what is the perimeter of the new rectangular farm formed by increasing the length of the field by 50% and reducing the width by 50%? About the author Sadie
Answer: 200cm Step-by-step explanation: by increasing the length of field by 50% the new length is = 60 + 60 × 50/100 = 60+30 =90m by decreasing the width of field by 50% the new width is = 20- 20×50/100 = 20 – 10 = 10m the new perimeter of rectangular farm = 2(l+b)= 2( 90 + 10) = 2×100 = 200m Reply
Answer: 200 m Step-by-step explanation: Original length = 60 m breadth = 20 m New length = original + 50% of original = 60 + 50% of 60 = 60 + (50/100 × 60) = 90 m New breadth = original – 50% of original = 20 – 50% of 20 = 20 – (50/100 × 20) = 10 m New perimeter = 2(length + breadth) = 2(90 + 10) = 200 m Reply
Answer:
200cm
Step-by-step explanation:
Answer:
200 m
Step-by-step explanation:
Original length = 60 m
breadth = 20 m
New length = original + 50% of original
= 60 + 50% of 60
= 60 + (50/100 × 60)
= 90 m
New breadth = original – 50% of original
= 20 – 50% of 20
= 20 – (50/100 × 20)
= 10 m
New perimeter = 2(length + breadth)
= 2(90 + 10)
= 200 m