The hypoenuse of a right triangle is 25 cm. We know that the difference in lengths of the other two sides is 5 cm. We would like to find out the length of the two sides ? About the author Piper
Answer: 20 or 15 Step-by-step explanation: Let the one side of triangle be x cm the other side be (x-5)cm ATP x to the power 2 + (x-5) to the power 2= 625 x to the power 2+ x to the power 2- 10x+25=625 2x to the power 2 – 10x+ 25-625=0 2(x to the power 2-5x+300)=0 x to the power 2-(20-15)x + 300=0 x to the power 2-20x+15x +300=0 x(x-20)-15(x-20)=0 (x-20)(x-15)=0 IF x-20=0 x=20 EITHER x-15=0 x=15 Reply
Answer:
20 or 15
Step-by-step explanation:
Let the one side of triangle be x cm
the other side be (x-5)cm
ATP
x to the power 2 + (x-5) to the power 2= 625
x to the power 2+ x to the power 2- 10x+25=625
2x to the power 2 – 10x+ 25-625=0
2(x to the power 2-5x+300)=0
x to the power 2-(20-15)x + 300=0
x to the power 2-20x+15x +300=0
x(x-20)-15(x-20)=0
(x-20)(x-15)=0
IF
x-20=0
x=20
EITHER
x-15=0
x=15