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The general solution of p2 – 1 = 0 is
y2 – 2yc – x2 + 2 = 0
y? – x2 = 42
y2 – 2yc + x2 + 2 = 0
32
2xy + x

By Sophia

The general solution of p2 – 1 = 0 is
y2 – 2yc – x2 + 2 = 0
y? – x2 = 42
y2 – 2yc + x2 + 2 = 0
32
2xy + x2 + c = 0
This restions Marked Forzo​

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Sophia

A bag contains 7 white balls and 5
black balls In how many ways 4
balls can be drawn form the bag if 2
must be whit

10. If – 1 is a zero of the polynomial f(x) = x² – 7x – 8, then the other zero is
a) 6
b)8
c)-8
d) 1​

1 thought on “The general solution of p2 – 1 = 0 is<br />y2 – 2yc – x2 + 2 = 0<br />y? – x2 = 42<br />y2 – 2yc + x2 + 2 = 0<br />32<br />2xy + x”

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