The flour in a bag is divided into three portions in the ratio of 2:5:7. If the smallest portion weighs 40 kg, how
much heavi

2 thoughts on “The flour in a bag is divided into three portions in the ratio of 2:5:7. If the smallest portion weighs 40 kg, how<br />much heavi”

1. Let the largest portion be as x

   then according. to the question …

   2:5:7 will be assumed as….

   2+5+7= 14

   2/14 of x = 40

   = x = 40*14/2

   = x =280kg

   then respectively

   112kg

   and 80kg

   therefore…

   280 – 40

   = 220 kg

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2. Answer:

   1 portion weighs = 40 kg

   2nd portion weighs = 200kg

   3rd portion weighs = 280 kg

   Step-by-step explanation:

   so the 2nd portion weighs 40×5

   = 200 kg

   the third portion weighs =

   40×7=

   280 kg respectively

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