the floor of a room in rectangular in shape its length is 6 cm and breadth is 5 metre height of the room is 4 metre find the area of the four walls of the room About the author Emery

Dimensions of the rectangular room=6m×5m×4m where l=6m, b=5m and h=4m Total Surface area of the four walls=Lateral surface area of the cuboid ⇒Total Surface area of the four walls=2(bh+lh) =2h(b+l) =2×4(5+6) =88sq.m ∴Total Surface area of the four walls=88sq.m Reply

Answer: Sorry I think you have got the question wrong I’m answering the question for 6m instead of 6cm I hope that is what you wanted. Step-by-step explanation: The answer will be 2(24+20) i.e.88 Reply

Dimensions of the rectangular room=6m×5m×4m

where l=6m, b=5m and h=4m

Total Surface area of the four walls=Lateral surface area of the cuboid

⇒Total Surface area of the four walls=2(bh+lh)

=2h(b+l)

=2×4(5+6)

=88sq.m

∴Total Surface area of the four walls=88sq.m

Answer:Sorry I think you have got the question wrong

I’m answering the question for 6m instead of 6cm

I hope that is what you wanted.

Step-by-step explanation:The answer will be 2(24+20)

i.e.88