The floor of a building consists of 2000 tiles of rhombus shape.
The diagonals of each tile are 40 cm and 30 cm in length.Fi

2 thoughts on “The floor of a building consists of 2000 tiles of rhombus shape.<br /> The diagonals of each tile are 40 cm and 30 cm in length.Fi”

1. Answer:

   6000

   Step-by-step explanation:

   We know, the area of a rhombus is given by the product of its diagonals. In this case, we have

   [tex]d1 = 40 \: cm \: and \: d2 = 30 \: cm[/tex]

   So,

   [tex]ar(rhbs.) = (40 \times 30 ) {cm}^{2} \\ = 1200 \: {cm}^{2} = \frac{1200 }{10000} \: {m}^{2} \\ = 0.12 \: {m}^{2} \: per \: tile[/tex]

   Given, there are total 2000 tiles and the cost of each square metre is Rs. 25 so,

   total cost is

   [tex]2000 \: tiles \times( 0.12 \: {m}^{2}per \: tile )\times (rs. \: 25 \: per \: {m}^{2} ) \\ = rs. \: (2000 \times \frac{12}{100} \times 25 ) =rs. (\: 20 \times 12 \times 25) \\ = rs. (\: 500 \times 12) = rs. \: 6000[/tex]

   So, the total cost is Rupees 6000.

   Hope this helps you. PLEASE MARK ME AS THE BRAINLIEST.

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2. 35,000

   Step-by-step explanation:

   Area of tile (rhombus shaped) = product of diagonal

   = 40×30 cm

   = 70 cm sq.

   Area of 2000 tiles = 2,000 × 70

   = 1,40,000

   If 100 cm = 1 m

   then 1,40,000 cm = 1,40,000 ÷ 100

   = 1,400 m sq.

   Cost of polishing the floor = ₹25 × 1,400

   = ₹35,000

   Therefore, the cost of polishing the floor is ₹35,000

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