the figures show a square a regular Pentagon and a regular hexagon put together find the angles < DAE< DAB < CAE< BAC About the author Amaya
Step-by-step explanation: We know that, all angles of square are 90°. In regular pentagon, Sum of the angles of n-sided polygon = (n – 2) × 180° ⇒ S = (5 – 2) × 180° ⇒ S = 3 × 180° ⇒ S = 540° Measure of each interior angle ⇒ Sum of all interior angle divided by number of side = 540°/5 = 108° In regular hexagon, Sum of the angles of n-sided polygon = (n – 2) × 180° ⇒ S = (6 – 2) × 180° ⇒ S = 4 × 180° ⇒ S = 720° Measure of each interior angle ⇒ Sum of all interior angle divided by number of side = 720°/6 =120 Let us assume the point opposite ∠ PQS + ∠ RQS + ∠ PQR = 360° (pair of angles at a vertex) ⇒ 120° + 108° + ∠ PQR = 360° ⇒ 228° + ∠ PQR = 360° ⇒ ∠ PQR = 360° – 228° ⇒ ∠ PQR = 132° I HOPE THIS IS HELPFUL. Reply
Step-by-step explanation:
We know that, all angles of square are 90°.
In regular pentagon,
Sum of the angles of n-sided polygon = (n – 2) × 180°
⇒ S = (5 – 2) × 180°
⇒ S = 3 × 180°
⇒ S = 540°
Measure of each interior angle
⇒ Sum of all interior angle divided by number of side
= 540°/5 = 108°
In regular hexagon,
Sum of the angles of n-sided polygon = (n – 2) × 180°
⇒ S = (6 – 2) × 180°
⇒ S = 4 × 180°
⇒ S = 720°
Measure of each interior angle
⇒ Sum of all interior angle divided by number of side
= 720°/6 =120
Let us assume the point opposite
∠ PQS + ∠ RQS + ∠ PQR = 360° (pair of angles at a vertex)
⇒ 120° + 108° + ∠ PQR = 360°
⇒ 228° + ∠ PQR = 360°
⇒ ∠ PQR = 360° – 228°
⇒ ∠ PQR = 132°
I HOPE THIS IS HELPFUL.