The coach of a cricket team buys 7 bats and 6 balls for 13200. Later he buys 3 bats and 5 balls for 5900. find the cost of each ba

2 thoughts on “The coach of a cricket team buys 7 bats and 6 balls for 13200. Later he buys 3 bats and 5 balls for 5900. find the cost of each ba”

1. ✬ Bat = Rs 1800 ✬

   ✬ Ball = Rs 100 ✬

   Step-by-step explanation:

   Given:

   • Cost of 7 bats and 6 balls is Rs 13200.
   • Cost of 3 bats and 5 balls is Rs 5900.

   To Find:

   • What is the cost of each bat and ball ?

   Solution: Let the cost of each bat and ball be Rs x and y respectively.

   ➙ Cost of 7 bats = Rs 7x

   ➙ Cost of 6 balls = Rs 6y

   [tex]\implies{\rm }[/tex] 7x + 6y = 13200

   • Equation 1

   Now , In second case

   ➙ Cost of 3 bats = Rs 3x

   ➙ Cost of 5 balls = Rs 5y

   [tex]\implies{\rm }[/tex] 3x + 5y = 5900

   • Equation 2

   [ Multiplying 5 in equation 1 and 6 in equation 2 ]

   ➯ (7x + 6y) 5 = 13200 × 5

   • 35x + 30y = 66000ㅤㅤㅤeqⁿ i

   ➯ (3x + 5y) 6 = 5900 × 6

   • 18x + 30y = 35400ㅤㅤeqⁿ ii

   ㅤㅤㅤㅤㅤ35x + 30y = 66000

   ㅤㅤㅤㅤㅤ18x + 30y = 35400

   ㅤㅤㅤㅤㅤ–ㅤㅤ–ㅤㅤ–

   ㅤㅤㅤㅤ━━━━━━━━━━━━━━━

   ㅤㅤㅤㅤㅤ17x = 30600

   ∴ x = 30600/17 = 1800

   Now putting the value of x in equation 1.

   [tex]\implies{\rm }[/tex] 7 × 1800 + 6y = 13200

   [tex]\implies{\rm }[/tex] 6y = 13200 – 12600

   [tex]\implies{\rm }[/tex] y = 600/6

   [tex]\implies{\rm }[/tex] y = 100

   Hence, the cost of each bat and ball is Rs 1800 & Rs 100 respectively.

   Reply

2. Given :-

   The coach of a cricket team buys 7 bats and 6 balls for 13200. Later he buys 3 bats and 5 balls for 5900

   To Find :-

   Cost of one bat and ball

   Solution :-

   Let

   Price of bat = x

   Price of ball = y

   Now

   7 × x + 6 × y = 13200

   7x + 6y = 13200

   Multiply by 5

   5(7x + 6y) = 5(13200)

   35x + 30y = 66000(1)

   Now

   3 × x + 5 × y = 5900

   3x + 5y = 5900

   Multiply by 6

   6(3x + 5y) = 6(5900)

   18x + 30y = 35400

   Subtracting them

   (35x + 30y) – (18x + 30y) = 66000 – 35400

   35x + 30y – 18x – 30y = 30600

   35x – 18x = 30600

   17x = 30600

   x = 30600/17

   x = 1800

   By putting in 1

   35(1800) + 30y = 66000

   63000 + 30y = 66000

   30y = 66000 – 63000

   30y = 3000

   y = 3000/30

   y = 100

   [tex]\\[/tex]

   Reply