[tex] \green{circumference =2 \pi \: r }[/tex] [tex]2\pi \: r = 22 \\ 2 \times \frac{22}{7} \times r = 22 \\ 2 \times \frac{1}{7} \times r = 1 \\ r = \frac{7}{2} [/tex] [tex] \green{area \: of \: quadrant \: = \frac{1}{4} \times \pi \: r {}^{2} } [/tex] [tex] \frac{1}{4} \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \\ \frac{1}{4} \times 11 \times 7 \times \frac{7}{2} \\ [/tex] [tex] \frac{539}{8} = 67.375[/tex] [tex]67 \: cm {}^{2} \: (approx)[/tex] please mark me as brainliest Reply

[tex] \green{circumference =2 \pi \: r }[/tex]

[tex]2\pi \: r = 22 \\ 2 \times \frac{22}{7} \times r = 22 \\ 2 \times \frac{1}{7} \times r = 1 \\ r = \frac{7}{2} [/tex]

[tex] \green{area \: of \: quadrant \: = \frac{1}{4} \times \pi \: r {}^{2} } [/tex]

[tex] \frac{1}{4} \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \\ \frac{1}{4} \times 11 \times 7 \times \frac{7}{2} \\ [/tex]

[tex] \frac{539}{8} = 67.375[/tex]

[tex]67 \: cm {}^{2} \: (approx)[/tex]

please mark me as brainliest

I get the answer of this circle’s quadrant is 5.5sq m