The area of a rectangular plot is increased by30% and its width remain as it was before. Whatwill be the ratio between the area of newrectangle and the original rectangle?1. 13:102: 10:133. 7:34. 3:7 About the author Madelyn
Given :- Area of rectangular plot increased by 30% To find :- Ratio between new and original rectangle Solution :- Let the Original rectangle’s area = y New rectangle area (100 + increased percentage) of original rectangle [tex]\sf \bigg(100 + 30\bigg) \times y[/tex] [tex]\sf \dfrac{100 + 30}{100} \times y[/tex] [tex]\sf \dfrac{130}{100}\times y[/tex] [tex]\sf \dfrac{13}{10}y[/tex] Finding ratio [tex]\sf \dfrac{13}{10}y = y[/tex] [tex]\sf 13y = 10\times y[/tex] [tex]\sf 13y = 10y[/tex] [tex]\sf 13 =10[/tex] Ratio = 13:10 [Option A] Reply
Answer: 13 : 10 is the required answer. Step-by-step explanation: Given that: The area of a rectangular plot is increased by 30% and its width remain as it was before. To Find: What will be the ratio between the area of new rectangle and the original rectangle? Let us assume: Area of original rectangle be x cm². Finding the ratio between the area of new rectangle and the original rectangle: Area of new rectangle : Area of original rectangle ⟶ (100 + 30)% of x : x ⟶ 130% of x : x ⟶ 1.3 of x : x ⟶ 1.3x : x Cancelling x. ⟶ 1.3 : 1 Multiplying by 10. ⟶ (1.3 × 10) : (1 × 10) ⟶ 13 : 10 ∴ The ratio between the area of new rectangle and the original rectangle = 13 : 10 Reply
Given :-
Area of rectangular plot increased by 30%
To find :-
Ratio between new and original rectangle
Solution :-
Let the
Original rectangle’s area = y
New rectangle area
(100 + increased percentage) of original rectangle
[tex]\sf \bigg(100 + 30\bigg) \times y[/tex]
[tex]\sf \dfrac{100 + 30}{100} \times y[/tex]
[tex]\sf \dfrac{130}{100}\times y[/tex]
[tex]\sf \dfrac{13}{10}y[/tex]
Finding ratio
[tex]\sf \dfrac{13}{10}y = y[/tex]
[tex]\sf 13y = 10\times y[/tex]
[tex]\sf 13y = 10y[/tex]
[tex]\sf 13 =10[/tex]
Ratio = 13:10 [Option A]
Answer:
Step-by-step explanation:
Given that:
To Find:
Let us assume:
Finding the ratio between the area of new rectangle and the original rectangle:
Area of new rectangle : Area of original rectangle
⟶ (100 + 30)% of x : x
⟶ 130% of x : x
⟶ 1.3 of x : x
⟶ 1.3x : x
Cancelling x.
⟶ 1.3 : 1
Multiplying by 10.
⟶ (1.3 × 10) : (1 × 10)
⟶ 13 : 10
∴ The ratio between the area of new rectangle and the original rectangle = 13 : 10