The age of a father is four times the age of his son. Five years hence, the age of
father will be three times the age of hi

The age of a father is four times the age of his son. Five years hence, the age of
father will be three times the age of his son. Find their present ages

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  1. Answer:

    let the age of son be x .

    let the age of father be 4x

    after 5 years son’s age = x + 5

    after 5 years father’s age = 4x + 5

    4x + 5 = 3 ( x + 5 )

    4x + 5 = 3x + 15

    4x 3x = 15 5

    x = 10

    therefore,

    age of son = 10 years

    age of father = 4 × 10 = 40 years

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  2. Step-by-step explanation:

    let x be the age of the son

    therefore father’s age = 4x

    After 5 years

    4x+5= 3 (x+5)

    4x+5= 3x+15

    4x-3x= 15-5

    x= 10

    father’s age= 4x= 40

    their present ages are 10 and 40

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