The age of a father is four times the age of his son. Five years hence, the age of father will be three times the age of his son. Find their present ages About the author Adalynn
Answer: let the age of son be x . let the age of father be 4x after 5 years son’s age = x + 5 after 5 years father’s age = 4x + 5 4x + 5 = 3 ( x + 5 ) 4x + 5 = 3x + 15 4x – 3x = 15 – 5 x = 10 therefore, age of son = 10 years age of father = 4 × 10 = 40 years Reply
Step-by-step explanation: let x be the age of the son therefore father’s age = 4x After 5 years 4x+5= 3 (x+5) 4x+5= 3x+15 4x-3x= 15-5 x= 10 father’s age= 4x= 40 their present ages are 10 and 40 Reply
Answer:
let the age of son be x .
let the age of father be 4x
after 5 years son’s age = x + 5
after 5 years father’s age = 4x + 5
4x + 5 = 3 ( x + 5 )
4x + 5 = 3x + 15
4x – 3x = 15 – 5
x = 10
therefore,
age of son = 10 years
age of father = 4 × 10 = 40 years
Step-by-step explanation:
let x be the age of the son
therefore father’s age = 4x
After 5 years
4x+5= 3 (x+5)
4x+5= 3x+15
4x-3x= 15-5
x= 10
father’s age= 4x= 40
their present ages are 10 and 40