[tex]lf = sin2x \: then \: \frac{dy}{dx} at \: x = \frac{\pi}{2} is \\ option \\ 1)2 \\ 2) – 2 \\ 3) – 1 \\ 4)0[/tex]

[tex]lf = sin2x \: then \: \frac{dy}{dx} at \: x = \frac{\pi}{2} is \\ option \\ 1)2 \\ 2) – 2 \\ 3) – 1 \\ 4)0[/tex]

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  1. Answer:

    Given y=sin2x

    Differentiate on both sides w.r.t. x

    dx

    dy

    ​  

    =  

    dx

    d

    ​  

    (sin2x)

    =cos2x  

    dx

    d

    ​  

    (2x)

    ∴  

    dx

    dy

    ​  

    =2cos2x

    Step-by-step explanation:

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