[tex]{\large{\underbrace{\textsf{\textbf{\color{red}{➵}{\color{green}{\:\:Question\: :-}}}}}}}[/tex]☞ The expression to be subtracted from -5×2 + 2x + 3 to get x2 – 3x – 1 is ____________. ☜ Only For ItzNawaabzadi12* About the author Natalia
Question:- The expression to be subtracted from -5×2 + 2x + 3 to get x2 – 3x – 1 is ____________. Answer:- Let The Polynomial That Subtracted be p(X) [tex]- 5x ^{2} + 2x + 3 \: – p(x) \: = {x}^{2} – 3x – 1 \\ \\ – 5x^{2} – x ^{2} + 2x – 3x + 3 – 1 = p(x) \\ \\ p(x) = 6x {}^{2} – x + 2[/tex] Reply
Answer: Let the polynomial to be subtracted be p(x) -5x² + 2x + 3 – p(x) = x² – 3x – 1 -5x² – x² + 2x – 3x + 3 – 1 = p(x) p(x) = -6x² – x + 2 HOPE IT HELPS #NAWABZAADI Reply
Question:-
The expression to be subtracted from -5×2 + 2x + 3 to get x2 – 3x – 1 is ____________.
Answer:-
Let The Polynomial That Subtracted be p(X)
[tex]- 5x ^{2} + 2x + 3 \: – p(x) \: = {x}^{2} – 3x – 1 \\ \\ – 5x^{2} – x ^{2} + 2x – 3x + 3 – 1 = p(x)
\\ \\ p(x) = 6x {}^{2} – x + 2[/tex]
Answer:
Let the polynomial to be subtracted be p(x)
-5x² + 2x + 3 – p(x) = x² – 3x – 1
-5x² – x² + 2x – 3x + 3 – 1 = p(x)
p(x) = -6x² – x + 2
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