[tex]\Huge{\textbf{\textsf{{\color{navy}{Quê}}{\purple{sTi}}{\pink{øN}}{\color{pink}{:}}}}}[/tex]
→ Given that (k-7) is the H.C.F. of 56 and 104, find the value of k. ←
~Only for ItzNawaabzadi12*
[tex]\Huge{\textbf{\textsf{{\color{navy}{Quê}}{\purple{sTi}}{\pink{øN}}{\color{pink}{:}}}}}[/tex]
→ Given that (k-7) is the H.C.F. of 56 and 104, find the value of k. ←
~Only for ItzNawaabzadi12*
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[tex]\huge{\underline{\underline{\bf{\purple{Answer}}}}}[/tex]
HCF ( 56 , 104 ) = 0
K – 7 = 0
K = 7
Hence , value of k = 7 .
Answer:
[tex]\huge\mathfrak\pink{Answer!}[/tex]
The Highest Common factor of 56 and 104 is 8
It is given that (k-7) is the HCF of 56 and 104
so, k-7 = 8
k = 8 + 7
k = 15
Therefore the value of k is 15
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