[tex]\huge\mathcal\red{Question} [/tex] Find HCF of numbers 1405,1465and 1530 {By Euclids division algorithm} About the author Jade
Answer: 1405, 1465 and 1530 Now, 1405 < 1465 1465 = 1405 × 1 + 60 1405 = 60 × 23 + 25 60 = 25 × 2 + 10 25 = 10 × 2 + 5 10 = 5 × 2 + 0 HCF OF 1405 AND 1465 = 5 Again, 5 and 1530 5 < 1530 1530 = 5 × 306 + 0 Answer=5 Reply
Answer:
1405, 1465 and 1530
Now,
1405 < 1465
1465 = 1405 × 1 + 60
1405 = 60 × 23 + 25
60 = 25 × 2 + 10
25 = 10 × 2 + 5
10 = 5 × 2 + 0
HCF OF 1405 AND 1465 = 5
Again,
5 and 1530
5 < 1530
1530 = 5 × 306 + 0
Answer=5
Answer:
HCF of
1405, 1465 &1530 is 5
LCM of 1405 =2152085