[tex] \frac{ \sqrt{3 } + \sqrt{2} }{ \sqrt{3} – \sqrt{2} } = a + b \sqrt{6} [/tex]
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1 thought on “<br />[tex] \frac{ \sqrt{3 } + \sqrt{2} }{ \sqrt{3} – \sqrt{2} } = a + b \sqrt{6} [/tex]<br />​”

1. Answer:

   a = 5 and b = 2

   Step-by-step explanation:

   (√3+√2)/(√3-√2) × (√3+√2)/(√3+√2)

   (√3+√2)²/(√3-√2)(√3+√2)

   (√3)²+(√2)²+2(√3)(√2)/(√3)²-(√2)²

   3+2+2√6/3-2

   5+2√6

   comparing with a+b√6,

   5+2√6 = a+b√6

   we get a = 5 and b = 2

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