[tex] \frac{2 – \sqrt{5} }{2 + \sqrt{5} } = a \sqrt{5 } + b[/tex]

[tex] \frac{2 – \sqrt{5} }{2 + \sqrt{5} } = a \sqrt{5 } + b[/tex]

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2 thoughts on “<br />[tex] \frac{2 – \sqrt{5} }{2 + \sqrt{5} } = a \sqrt{5 } + b[/tex]<br />​”

  1. Answer:

    a = (-4) and b = (-9)

    Step-by-step explanation:

    (2-√5)/(2+√5) × (2-√5)/(2-√5)

    (2-√5)²/(2-√5)(2+√5)

    (2)²+(√5)²+2(2)(√5)/(2)²-(√5)²

    4+5+4√5/4-5

    9+4√5/(-1)

    => (-9-4√5)

    comparing with a√5+b,

    -4√5-9 = a√5+b

    -4√5+(-9) = a√5+b

    now, a = (-4) and b = (-9).

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