[tex]fill \: the \: box \: \frac{3}{5} | \: \: \: \: | \frac{12}{91} [/tex]


fill the box 3/5__12/91

[tex]fill \: the \: box \: \frac{3}{5} | \: \: \: \: | \frac{12}{91} [/tex]

fill the box 3/5__12/91​

About the author
Natalia

2 thoughts on “<br />[tex]fill \: the \: box \: \frac{3}{5} | \: \: \: \: | \frac{12}{91} [/tex]<br /><br /><br />fill the box 3/5__12/91”

  1. Answer:

    The LCM of 5 and 91 is 455.

    [tex] \frac{3}{5} = \frac{3 \times 91}{5 \times 91} = \frac{273}{455} [/tex]

    [tex] \frac{12}{91} = \frac{12 \times 5}{91 \times 5} = \frac{60}{455} [/tex]

    since,

    [tex]273 > 60[/tex]

    therefore,

    [tex] \frac{273}{455} > \frac{60}{455} [/tex]

    [tex] = > \: \frac{3}{5} > \frac{12}{91} [/tex]

    HOPE IT WORKS OUT FOR YOU AND PLEASE F-O-L-L-O-W ME AND MARK ME BRAINLIEST.

    Reply
  2. Answer:

    L.C.M. of 5 and 91 = 5 × 91 = 455

    [tex] \frac{3}{5} = \frac{3 \times 91}{5 \times 91} = \frac{273}{455} [/tex]

    [tex] \frac{12}{91} = \frac{12 \times 5}{91 \times 5} = \frac{60}{455} [/tex]

    Clearly,

    [tex]273 > 60 \\ = > \frac{273}{455} > \frac{60}{455} [/tex]

    Hence,

    [tex] \frac{3}{5} > \frac{12}{91} [/tex]

    Hope it helps you.

    Please mark my answer brainliest.

    Reply

Leave a Reply to Eliza Cancel reply