To factorise:- 98y²+168yz+72z² __________________________ Solution:- By rearranging the given equation: => 98y²+72z²+168yz Now adjusting it in the form of any algebraic identity. => (7√2y)²+ (6√2z)²+2(7√2y)(6√2z) Now we can see that this is in the form of a²+b²+2ab=(a+b)² where a=7√2y and b=6√2z. So, => (7√2y+6√2z)² Hence factorised __________________________ Reply
To factorise:-
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Solution:-
By rearranging the given equation:
=> 98y²+72z²+168yz
Now adjusting it in the form of any algebraic identity.
=> (7√2y)²+ (6√2z)²+2(7√2y)(6√2z)
Now we can see that this is in the form of a²+b²+2ab=(a+b)² where a=7√2y and b=6√2z.
So,
=> (7√2y+6√2z)²
Hence factorised
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