tan(90 -θ) + cot(90 – θ)/cosecθ= secθ


Prove the condition given above​

tan(90 -θ) + cot(90 – θ)/cosecθ= secθ

Prove the condition given above​

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1 thought on “tan(90 -θ) + cot(90 – θ)/cosecθ= secθ <br /><br /><br />Prove the condition given above​”

  1. Answer:there is ur answer

    Explanation: Evaluate sec²36-cot²54/cosec²33-tan² 57+cot theta tan(90-theta)-sec (90-theta)cosec theta

    there is ur answer

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