taking the length of the perpendicular as h prove the h/2 = ³/h

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taking the length of the perpendicular as h prove the h/2 = ³/h

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Answer:hhjhjhhjjugcygcvg has built h

Answer:In the given figure

EC=

2

S

AE=

2

3

S

AS c

′

is the centroid of △ABC

⇒C

′

E=

3

1

AE=

2

3

S

CC

′

=

3

S

Now, In △DC

′

C

Using Pythagoras theorem

(DC

′

)

2

=(CC

′

)

2

+(CD)

2

h

2

+

3

S

2

=S

2

⇒h

2

=

3

2S

2

⇒S

2

=

2

3h

2