taking the length of the perpendicular as h prove the h/2 = ³/h
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taking the length of the perpendicular as h prove the h/2 = ³/h
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Answer:
hhjhjhhjjugcygcvg has built h
Answer:
In the given figure
EC=
2
S
AE=
2
3
S
AS c
′
is the centroid of △ABC
⇒C
′
E=
3
1
AE=
2
3
S
CC
′
=
3
S
Now, In △DC
′
C
Using Pythagoras theorem
(DC
′
)
2
=(CC
′
)
2
+(CD)
2
h
2
+
3
S
2
=S
2
⇒h
2
=
3
2S
2
⇒S
2
=
2
3h
2