taking the length of the perpendicular as h prove the h/2 = ³/h​

2 thoughts on “taking the length of the perpendicular as h prove the h/2 = ³/h​”

1. Answer:

   hhjhjhhjjugcygcvg has built h

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2. Answer:

   In the given figure

   EC=

   2

   S

   AE=

   2

   3

   S

   AS c

   ′

   is the centroid of △ABC

   ⇒C

   ′

   E=

   3

   1

   AE=

   2

   3

   S

   CC

   ′

   =

   3

   S

   Now, In △DC

   ′

   C

   Using Pythagoras theorem

   (DC

   ′

   )

   2

   =(CC

   ′

   )

   2

   +(CD)

   2

   h

   2

   +

   3

   S

   2

   =S

   2

   ⇒h

   2

   =

   3

   2S

   2

   ⇒S

   2

   =

   2

   3h

   2

   Reply