Susie begins a new walking program with 600 m on the first day. Each day, she will increase her walk by 200 m. How many kilometers will she walk on day 4 of her program?
The following sum can be solved by a sequence concept .
For the following sum/problem it is given that , each day , he distance Susie walks will increase by 200 km . So it means that her walk is progressing and will be differ by 200km , so that is why we need to solve this by arithmetic sequence .
Formal to be used -:
aₙ = a₁ + (n – 1) (d)
where aₙ is the nth term, a₁ is the first term, and d is the common difference
[tex] \underline \purple{Given →}[/tex]
→a₁ = 600 m (distance in the beginning)
→n = 4(because we are solving for the distance for the 4th day)
→d = 200 m
[tex] \underline \purple{Solution:}[/tex]
aₙ = a₁ + (n – 1) (d)
a₁₈ = 600 m + (4-1)(200 m)
a₁₈ = m = 1.2km( in meter 1200 m)
[tex] \underline \bold \red{Therefore \: , \: Susie \: will \: walk \: 1.2 km \: on \: the \: 4th \: day \: of \: her \: program}[/tex]
Answer:
1200 this is the answer
plz follow
Answer:
The following sum can be solved by a sequence concept .
For the following sum/problem it is given that , each day , he distance Susie walks will increase by 200 km . So it means that her walk is progressing and will be differ by 200km , so that is why we need to solve this by arithmetic sequence .
Formal to be used -:
aₙ = a₁ + (n – 1) (d)
where aₙ is the nth term, a₁ is the first term, and d is the common difference
[tex] \underline \purple{Given →}[/tex]
→a₁ = 600 m (distance in the beginning)
→n = 4(because we are solving for the distance for the 4th day)
→d = 200 m
[tex] \underline \purple{Solution:}[/tex]
aₙ = a₁ + (n – 1) (d)
a₁₈ = 600 m + (4-1)(200 m)
a₁₈ = m = 1.2km( in meter 1200 m)
[tex] \underline \bold \red{Therefore \: , \: Susie \: will \: walk \: 1.2 km \: on \: the \: 4th \: day \: of \: her \: program}[/tex]
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