Answer: the 2 no.s are 4 and 11 Step-by-step explanation: let x and y be the 2 no.s given, that x+y = 15 and x-y=7 consider, (x+y) + (x-y) => (x+y) + (x-y) = 15+7 => 2x = 22 => x = 22/2 => x = 11 so, substitute x=11 in x+y=15 => 11+y = 15 => y = 15-11 => y = 4 so, the 2 no.s are 4 and 11 Reply
Answer: The numbers are 4 and 11 Step-by-step explanation: let x and y be the 2 no.s given, that x+y = 15 and x-y=7 consider, (x+y) + (x-y) = (x+y) + (x-y) = 15+7 = 2x = 22 = x = 22/2 = x = 11 on substituting x=11 in x+y=15, we get =11+y = 15 = y = 15-11 = y = 4 ∴The 2 no.s are 4 and 11 Hope it helps Please mark as brainliest Reply
Answer:
the 2 no.s are 4 and 11
Step-by-step explanation:
let x and y be the 2 no.s
given, that x+y = 15 and x-y=7
consider, (x+y) + (x-y)
=> (x+y) + (x-y) = 15+7
=> 2x = 22
=> x = 22/2
=> x = 11
so, substitute x=11 in x+y=15
=> 11+y = 15
=> y = 15-11
=> y = 4
so, the 2 no.s are 4 and 11
Answer:
The numbers are 4 and 11
Step-by-step explanation:
let x and y be the 2 no.s
given, that x+y = 15 and x-y=7
consider, (x+y) + (x-y)
= (x+y) + (x-y) = 15+7
= 2x = 22
= x = 22/2
= x = 11
on substituting x=11 in x+y=15, we get
=11+y = 15
= y = 15-11
= y = 4
∴The 2 no.s are 4 and 11
Hope it helps
Please mark as brainliest