Subtract b (b^2+ b-7) from 3b^2 -8 and find the value of expression obtained for b= -3​

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1. Answer:

   Hope it helps you!!

   Step-by-step explanation:

   (3b²-8)-b(b²+b-7)

   = 3b²-8-b³-b²+7b

   = -b³+3b²-b²+7b-8

   = -b³+2b²+7b-8 ans.

   when b = -3

   -(-3)³+3(-3)²+7(-3)-8

   = -(-27)+3(9)-21-8

   =27+27-21-8

   =54-29

   =25

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