Subtract: 3a (a+b+c) – 2b(a – b + c ) from 4c ( – a + b + c )
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Subtract: 3a (a+b+c) – 2b(a – b + c ) from 4c ( – a + b + c )
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Answer:
3a (a + b + c) − 2b (a − b + c) = 3a2 +3ab + 3ac − 2ba + 2b2 − 2bc = 3a2 + 2b2 + ab + 3ac − 2bc 4c (− a + b + c) = − 4ac + 4bc + 4c2 Subtracting these expressions, we obtain Therefore, the result is −3a2 −2b2 + 4c2 − ab + 6bc − 7acRead more on Sarthaks.com – https://www.sarthaks.com/108582/subtract-3a-a-b-c-2b-a-b-c-from-4c-a-b-c