Answer: solution, 3a(a+b+c)-2b(a-b+c) =3a²+3ab+3ac-2ab+2b²-2bc =(3a²+2b²+ab+3ac-2bc)-4c(-a+b+c) =3a²+2b²+ab+3ac-2bc+4ac-4bc-4c² =3a²+2b²+ab+7ac-6ac-4c² Reply
Answer:
solution, 3a(a+b+c)-2b(a-b+c)
=3a²+3ab+3ac-2ab+2b²-2bc
=(3a²+2b²+ab+3ac-2bc)-4c(-a+b+c)
=3a²+2b²+ab+3ac-2bc+4ac-4bc-4c²
=3a²+2b²+ab+7ac-6ac-4c²