Given,2x-3y-8=0 and 4x-3y-16=0Given equation area in the general form ax1 + by1 + c1 = 0 and ax2+ by2 + c2 = 0. ax1 =2, by1 =-3, c1=-8, ax2 =4, by2 = -3 and c2 =-16 Here,ax1/ax2 is not equal to by1/by2So,it has a unique solution and it is consistent and it intersect Reply
Given,
2x-3y-8=0 and 4x-3y-16=0
Given equation area in the general form ax1 + by1 + c1 = 0 and ax2+ by2 + c2 = 0.
ax1 =2, by1 =-3, c1=-8, ax2 =4, by2 = -3 and c2 =-16
Here,
ax1/ax2 is not equal to by1/by2
So,it has a unique solution and it is consistent and it intersect