Solve the quadratic quation by
factarisation method
2y2 +27 y +13=0​

2 thoughts on “Solve the quadratic quation by<br />factarisation method<br />2y2 +27 y +13=0​”

1. Step-by-step explanation:

   2y^2 + 27y + 13 =0

   2y^2 + 26y + 1y + 13 =0

   2y ( y + 13 ) + 1 ( y + 13 ) = 0

   ( y + 13 ) (2y + 1)

   y + 13 = 0 , 2y + 1 = 0

   y = -13 , y = – 1/2

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2. Step-by-step explanation:

   2y²+ 26y + y +13 =0

   2y(y+13) + 1(y+13) =0

   (2y+1) (y+13) = 0

   y= -1/2 or -13

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