Solve :

[tex] \frac{2x}{x – 4 } + \frac{1}{x – 2} + \frac{2}{x {}^{2} – 6x + 8 } = 0[/tex]

# Solve :

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Step-by-step explanation:=x−4

2x

+

x−2

1

+

(x−4)(x−2)

2

=0

=2x(x−2)+x−4+2=0

=2x²−3x−2=0

=2x²+x−4x−2=0

=x(2x+1)−2(2x+1)=0

=(2x+1)(x−2)=0

=x=− 1/2;2

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