Answer: Step-by-step explanation: If cosθ=-√3/2, Then,squaring on both sides,we get. =>cos²θ=(-√3/2)² =>cos²θ=3/4 =>1/cos²θ =4/3 =>sec²θ =4/3, [because 1/cosθ=secθ] =>1+tan²θ =4/3, [because sec²θ- tan²θ=1] =>tan²θ =4/3 – 1 tanθ =±√(1/3) As we know that tanθ is negative in 2nd quadrant So, tanθ =–√(1/3),Ans. Reply
Answer:
Step-by-step explanation:
If cosθ=-√3/2,
Then,squaring on both sides,we get.
=>cos²θ=(-√3/2)²
=>cos²θ=3/4
=>1/cos²θ =4/3
=>sec²θ =4/3, [because 1/cosθ=secθ]
=>1+tan²θ =4/3, [because sec²θ- tan²θ=1]
=>tan²θ =4/3 – 1
tanθ =±√(1/3)
As we know that tanθ is negative in 2nd quadrant
So, tanθ =–√(1/3),Ans.